Question

A force of 50N acts on the object of mass of 20 kg. shown in the figure. Calculate the acceleration of the object in x and y directions.

 

Answer 1

Given F = 50 N and m = 20 kg

(1) component of force along x – direction

F_x = F cos θ

= 50 × cos 30° = 43.30 N

a_x = `F_x/m` = `43.30/20` =2.165 ms^-2

(2) Component of force along y – direction

F_y = F sin θ = 50 sin 30° = 25 N

a_y = `F_y/m` = `25/20` = 1.25 ms^-2