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Question
A fair die is tossed. Let X denote 1 or 3 according as an odd or an even number appears. Find the probability distribution, mean and variance of X.
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Solution
Let X be 1 for the appearance of odd numbers 1, 3 or 5 on the die. Then,
\[P\left( X = 1 \right) = \frac{3}{6} = \frac{1}{2}\]
Let X be 3 for the appearance of even numbers 2, 4 or 6 on the die. Then,
\[P\left( X = 3 \right) = \frac{3}{6} = \frac{1}{2}\]
Thus, the probability distribution of X is given by
| x | P(X) |
| 1 |
\[\frac{1}{2}\]
|
| 2 |
\[\frac{1}{2}\]
|
Computation of mean and variance
|
xi |
pi | pixi | pixi2 | |
| 1 |
\[\frac{1}{2}\]
|
\[\frac{1}{2}\]
|
\[\frac{1}{2}\]
|
|
| 3 |
\[\frac{1}{2}\]
|
\[\frac{3}{2}\]
|
\[\frac{9}{2}\]
|
|
| `∑`pixi = 2 | `∑`pixi2 = 5 |
|
\[\text{ Mean } = \sum p_i x_i = 2\]
\[\text{ Variance } = \sum p_i {x_i}2^{}_{} - \left( \text{ Mean} \right)^2 \]
\[ = 5 - 4\]
\[ = 1\]
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