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Question
A disc of radius 0.4 m and mass 1 kg rotates about an axis passing through it centre and perpendicular to its plane. The angular acceleration is 10 rad/s2. The tangential force applied to the rim of the disc is ______.
Options
2 N
4 N
3 N
1 N
MCQ
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Solution
A disc of radius 0.4 m and mass 1 kg rotates about an axis passing through it centre and perpendicular to its plane. The angular acceleration is 10 rad/s2. The tangential force applied to the rim of the disc is 2 N.
Explanation:
Moment of inertia = I = `"MR"^2/2`
`= (1 xx (0.4)^2)/2`
= 0.08 kg-m2
Torque τ = Iα = 0.08 × 10 = 0.8 N-m
τ = rF
`therefore "F" = tau/"r" = 0.8/0.4` = 2N
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Expression for Torque in Terms of Moment of Inertia
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