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Question
A die has its six faces marked 0, 1, 1, 1, 6, 6. Two such dice are thrown together and the total score is recorded. What is the probability of getting a total of 7?
Sum
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Solution
Given, a die has its six faces marked {0, 1, 1, 1, 6, 6}
∴ Total sample space, n(S) = 62 = 36
Let E = Event of getting a sum 7
= {(1, 6), (1, 6), (1, 6), (1, 6), (1, 6), (1, 6), (6, 1), (6, 1), (6, 1), (6, 1), (6,1), (6,1)}
∴ n(E) = 12
∴ `P(E) = (n(E))/(n(S)) = 12/36 = 1/3`
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