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Question
A cuboid has total surface area of 50 m2 and lateral surface area is 30 m2. Find the area of its base.
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Solution
\[\text { Total sufrace area of the cuboid } = 50 m^2 \]
\[\text { Its lateral surface area = }30 m^2 \]
\[\text { Now, total surface area of the cuboid = 2 }\times (\text { surface area of the base) }+ \text { (surface area of the 4 walls) }\]
\[ \Rightarrow 50 = 2 \times\text { (surface area of the base) } + (30)\]
\[ \Rightarrow 2 \times\text { (surface area of the base) }= 50 - 30 = 20\]
\[ \therefore \text { Surface area of the base } = \frac{20}{2} = 10 m^2\]
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