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Question
A cricketer scored a total of 62 runs in 96 balls. He hit 3 sixes, 8 fours, 2 twos and 8 singles. What percentage of the total runs came in
(i) Sixes
(ii) fours
(iii) twos
(iv) singles
Numerical
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Solution
(i) The cricketer hits 3 sixes.
\[i . e . , 3 \times 6 = 18\]
\[ \therefore \frac{18}{62} \times 100 = 29 . 03 \% \]
(ii) The cricketer hits 8 fours.
\[i . e . , 8 \times 4 = 32\]
\[ \therefore \frac{32}{62} \times 100 = 51 . 61 \% \]
(iii) The cricketer hits 2 twos.
\[i . e . , 2 \times 2 = 4\]
\[ \therefore \frac{4}{62} \times 100 = 6 . 45 \% \]
(iv) The cricketer hits 8 singles.
\[i . e . , 8 \times 1 = 8\]
\[ \therefore \frac{8}{62} \times 100 = 12 . 90 \%\]
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