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A covalent bond in tert-butyl bromide breaks in a suitable polar solvent to give ions. A. Name the anion produced by this breaking of a covalent bond. B. Indicate the type of bond breaking in this - Chemistry

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Question

A covalent bond in tert-butyl bromide breaks in a suitable polar solvent to give ions.
  1. Name the anion produced by this breaking of a covalent bond.
  2. Indicate the type of bond breaking in this case.
  3. Comment on the geometry of the cation formed by such bond cleavage.
Chemical Equations/Structures
Short Answer
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Solution

  1. \[\begin{array}{cc}
    \ce{CH3}\phantom{..............}\ce{CH3}\phantom{.........}\\
    |\phantom{..................}|\phantom{............}\\
    \ce{H3C - C - Br} \ce{->[aq]} \ce{H3C - C^\oplus} + \ce{\underset{Bromide ion (anion)}{Br-}}\\
    |\phantom{..................}|\phantom{............}\\
    \ce{CH3}\phantom{..........}\ce{\underset{tert-butyl Cation}{CH3}}\phantom{.....}\\
    \end{array}\]
  2. Heterolytic cleavage/fission takes place as charged ions are produced.
  3. tert-Butyl carbocation formed in the given cleavage has trigonal planar geometry.
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Chapter 14: Basic Principles of Organic Chemistry - Exercises [Page 232]

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Balbharati Chemistry [English] Standard 11 Maharashtra State Board
Chapter 14 Basic Principles of Organic Chemistry
Exercises | Q 14. | Page 232
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