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Question
A conducting sphere of radius 'R' is given a charge 'Q' uniformly. The electric field and the electric potential at the centre of the sphere are respectively [ε0 = permittivity of free space] ______.
Options
zero and \[\frac{Q}{4\pi\varepsilon_{0}R}\]
\[\frac{Q}{4\pi\varepsilon_{0}R^2}\] and zero
\[\frac{Q}{4\pi\varepsilon_{0}R}\] and \[\frac{Q}{4\pi\varepsilon_{0}R^2}\]
zero and zero
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Solution
A conducting sphere of radius 'R' is given a charge 'Q' uniformly. The electric field and the electric potential at the centre of the sphere are respectively [ε0 = permittivity of free space] zero and \[\frac{Q}{4\pi\varepsilon_{0}R}\].
Explanation:
For a conducting sphere, all charge resides on the surface, so the electric field inside (including the centre) is zero by Gauss's Law, while the potential everywhere inside equals the surface potential \[\frac {Q}{4πε_0R}\] since no work is done moving a charge inside a conductor.
