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Question
A concave mirror of radius of curvature 16 cm produces two-times enlarged real image of an object kept in front of it. Find the position of the object.
Numerical
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Solution
Given: Radius of curvature (R) = −16 cm (concave mirror)
Focal length (f) = `(-16)/2` = −8 cm
The image is real and enlarged two times, so m = −2 ...(magnification is negative for real images).
From m = `-v/u`,
−2 = `-v/u`
⇒ v = 2u
Now, using the mirror formula:
`1/f = 1/v + 1/u`
`1/-8 = 1/(2 u) + 1/u`
`1/-8 = (1+ 2)/(2 u)`
`1/-8 = 3/(2 u)`
2u = −24
u = −12 cm
∴ The object is placed at a distance of 12 cm in front of the mirror.
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