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Question
A compound (A) of boron reacts with NMe3 to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A, B and C. Give the reactions involved.
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Solution
\[\ce{B2H6 (A) + 2NMe3 -> 2BH3NMe3 (B)}\]
\[\ce{BH3NHe3 + H2O -> H3BO3 (C) + NMe3 + 6H2}\]
(A): B2H6
(B): 2BH3NMe3
(C): H3BO3
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