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A coil of wire of a certain radius has 600 turns and a self-inductance is 108 mH. The self-inductance of a second similar coil of 500 turns will be: -

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Question

A coil of wire of a certain radius has 600 turns and a self-inductance is 108 mH. The self-inductance of a second similar coil of 500 turns will be:

Options

  • 74 mH

  • 75 mH

  • 76 H

  • 77 mH

MCQ

Solution

75 mH

Explanation:

As Ln2

∴ L = `108 xx (500/600)^2` mH = 75 mH.

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