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A Class Has 15 Students Whose Ages Are 14, 17, 15, 14, 21, 19, 20, 16, 18, 17, 20, 17, 16, 19 and 20 Years Respectively. - Mathematics

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Question

A class has 15 students whose ages are 14, 17, 15, 14, 21, 19, 20, 16, 18, 17, 20, 17, 16, 19 and 20 years respectively. One student is selected in such a manner that each has the same chance of being selected and the age X of the selected student is recorded. What is the probability distribution of the random variable X?

Sum
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Solution

Here, X can take the values 14, 15, 16, 17, 19, 20 and 21.
Now,

\[P\left( X = 14 \right) = \frac{2}{15}\]
\[P\left( X = 15 \right) = \frac{1}{15}\]
\[P\left( X = 16 \right) = \frac{2}{15}\]
\[P\left( X = 17 \right) = \frac{3}{15}\]
\[P\left( X = 18 \right) = \frac{1}{15}\]
\[P\left( X = 19 \right) = \frac{2}{15}\]
\[P\left( X = 20 \right) = \frac{3}{15}\]
\[P\left( X = 21 \right) = \frac{1}{15}\]

Thus, the probability distribution of X is given by

X P(X)
14
 
\[\frac{2}{15}\]
15
 
\[\frac{1}{15}\]
16
 
\[\frac{2}{15}\]
17
 
\[\frac{3}{15}\]
18
 
\[\frac{1}{15}\]
19
 
\[\frac{2}{15}\]
20
 
\[\frac{3}{15}\]
21
 
\[\frac{1}{15}\]
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Chapter 32: Mean and Variance of a Random Variable - Exercise 32.1 [Page 15]

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RD Sharma Mathematics [English] Class 12
Chapter 32 Mean and Variance of a Random Variable
Exercise 32.1 | Q 13 | Page 15
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