Advertisements
Advertisements
Question
A circle of the largest area is cut from a rectangular piece of cardboard with dimensions 55 cm and 42 cm. Find the ratio between the area of the circle cut and the area of the remaining card-board.
Advertisements
Solution
The largest area of the circle is possible when,
diameter = 42
Therefore, radius = `42/2` = 21 cm
Therefore, Area of circle = π × (21)2
= 1386
Area of the rectangle = 55 × 42 = 2310 cm2
Therefore, area of remaining cardboard-
`= 42 xx 55 - pi (21)^2`
`= 42 xx 55 - 22/7 (21)^2`
= 2310 - 1386
= 924
Hence, the volume of the circle and area remaining cardboard-
= 1386 : 924
= 231 : 154
= 3 : 2
APPEARS IN
RELATED QUESTIONS
A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path? (π = 3.14)

The area of a rectangular plot is ` 462m^2` and is length is 28 m. Find its perimeter.
Find the area of the quadrilateral ABCD in which AD = 24 cm, ∠BAD 90° and ∠BCD is an equilateral triangle having each side equal to 26 cm. Also, find the perimeter of the quadrilateral.
Find the area of minor segment of a circle of radius 14 cm, when the angle of the corresponding sector is 600 .
In the following figure, an equilateral triangle ABC of side 6 cm has been inscribed in a circle. Find the area of the shaded region. (Take π = 3.14).

What is the angle subtended at the centre of a circle of radius 6 cm by an arc of length 3 π cm?
If the circumference and the area of a circle are numerically equal, then diameter of the circle is
The perimeter of a triangle is 30 cm and the circumference of its incircle is 88 cm. The area of the triangle is
In the given figure, ABCD is a rectangle with AB = 80 cm and BC = 70 cm, ∠AED = 90° and DE = 42 cm. A semicircle is drawn, taking BC as diameter. Find the area of the shaded region.

The radii of the two circles are 4 cm and 3 cm respectively. The diameter of the circle having an area equal to the sum of the areas of the two circles (in cm) is ____________.
