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A charge particle after being accelerated through a potential difference ‘V’ enters in a uniform magnetic field and moves in a circle of radius r. If V is doubled, the radius of the circle will become - Physics

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Question

A charge particle after being accelerated through a potential difference ‘V’ enters in a uniform magnetic field and moves in a circle of radius r. If V is doubled, the radius of the circle will become ______.

Options

  • 2r

  • `sqrt 2` r

  • 4r

  • `r/sqrt 2`

MCQ
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Solution

A charge particle after being accelerated through a potential difference ‘V’ enters in a uniform magnetic field and moves in a circle of radius r. If V is doubled, the radius of the circle will become `bbunderline(sqrt 2 r)`.

Explanation:

When a charged particle is accelerated through a potential difference V, 

`1/2 mv^2` = qv

⇒ v = `sqrt((2 q V)/m)`

Radius in magnetic field:

r = `(m v)/(q B)`

Since v ∝ `sqrt V`,

∴ r ∝ `sqrt V`

If V is doubled,

r' = `sqrt 2 r`

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