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Question
A certain nucleus A (mass number 238 and atomic number 92) is radioactive and becomes a nucleus B (mass number 234 and atomic number 90) by the emission of a particle.
- Name the particle emitted.
- Explain how you arrived at your answer.
- State the change in the form of a reaction.
Answer in Brief
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Solution
\[\ce{^238_92A -> ^234_90B}\]
- α - particle
- ∵ Mass Number has decreased by 4 and atomic number has decreased by 2.
- This change can be expressed in the form of a reaction as follows:
\[\ce{\underset{Parent nucleus}{_92^238A} -> \underset{Daughter nucleus}{_90^234B} + \underset{(\alpha-particle)}{_2^4He}}\]
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Alpha Decay (Alpha Emission)
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