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Question
A card is drawn at random from a pack of 52 cards. Find the probability that the card drawn is not a diamond card
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Solution
Let S denote the sample space.
Then, n(S) = 52
Let E9 = event of not drawing a diamond card
Then
\[\bar{{E_9}}\]= event of drawing a diamond card
There are 13 diamond cards in a pack of 52 cards, out of which one diamond card can be drawn in 13C1
There are 13 diamond cards in a pack of 52 cards, out of which one diamond card can be drawn in 13C1
\[i . e . n\left( \bar{{E_9}} \right) = \frac{13}{52} = \frac{1}{4}\]
\[\therefore P\left( E_9 \right) = 1 - P\left( E_9 \right)\]
\[= 1 - \frac{1}{4} = \frac{3}{4}\]
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