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Question
A car moves at a constant speed on a road as shown in figure. The normal force by the road on the car NA and NB when it is at the points A and B respectively.
Options
NA = NB
NA > NB
NA < NB
insufficient
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Solution
NA < NB
From the figure in the question, it is clear that \[r_B > r_A\].
Here, normal reaction is inversely proportional to the centrifugal force acting on the car, while taking turn on the curve track. Also, centrifugal force is inversely proportional to the radius of the circular track.
Therefore, we have:
NA < NB
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