Question

A capillary is dipped in water vessel kept in a lift going up with acceleration 2 g. Then ______

Options

• The water will rise in the tube to the height observed under normal condition.

• Water will rise to the maximum available height of the tube.

• Water will rise to the height one third of the height of normal condition.

• Water will rise to the height double the height ofnormal condition.

Answer 1

A capillary is dipped in water vessel kept in a lift going up with acceleration 2 g. Then water will rise to the height one third of the height of normal condition.

Explanation:

We know that h = `(2 T cos θ)/(rρg)`

In a moving lift acceleration becomes = (g + a)

= (g + 2g)

= 3g

∴ `h' = (2T cos θ)/(rρ(3g))`

= `h/3`