Question

A bird is flying from A towards B at an angle of 35°, a point 30 km away from A. At B it changes its course of flight and heads towards C on a bearing of 48° and distance 32 km away. How far is C to the North of B?

(sin 55° = 0.8192, cos 55° = 0.5736, sin 42° = 0.6691, cos 42° = 0.7431)

Answer 1

Distance from C to the North of B is CD

In the right ∆BCD,

sin 42° = `"CD"/"BC"`

0.6691 = `"BD"/32`

∴ CD = 0.6691 × 32

= 21.41 km

Distance of C to the North B is 21.41 km