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A beaker is filled with water (refractive index 4/3) upto a height H. A coin is placed at its bottom. The depth of the coin, when viewed along the near normal direction, will be ______. - Physics

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Question

A beaker is filled with water (refractive index `4/3`) upto a height H. A coin is placed at its bottom. The depth of the coin, when viewed along the near normal direction, will be ______.

Options

  • `H/4`

  • `(3 H)/4`

  • H

  • `(4 H)/3`

MCQ
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Solution

A beaker is filled with water (refractive index `4/3`) upto a height H. A coin is placed at its bottom. The depth of the coin, when viewed along the near normal direction, will be `bbunderline((3 H)/4)`.

Explanation:

Given: Refractive index of water (n) = `4/3`

Actual depth of the coin (H) 

Apparent depth (h)

Formula for Refractive Index:

Refraction index = `"Real depth"/"Apparent depth"`

n = `H/h`

h = `H/n`

Putting values,

h = `H xx 3/4`

= `(3 H)/4`

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