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Question
A ball is projected with kinetic energy E, at an angle of 60° to the horizontal. The kinetic energy of this ball at the highest point of its flight will become ______.
Options
Zero
`"E"/2`
`"E"/4`
E
MCQ
Fill in the Blanks
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Solution
A ball is projected with kinetic energy E, at an angle of 60° to the horizontal. The kinetic energy of this ball at the highest point of its flight will become `bb("E"/4)`.
Explanation:
We only have the horizontal component of velocity at the highest point. So, Velocity v = u cos60°
= `"u"/2`
∴ K.E at top most point = `1/2"m"("u"/2)^2="E"/4`
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Helical Motion
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