Advertisements
Advertisements
Question
A bag contains twenty Rs 5 coins, fifty Rs 2 coins and thirty Re 1 coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin will neither be a Rs 5 coin nor be a Re 1 coin?
Sum
Advertisements
Solution
Total number of coins = 20 + 50 + 30 = 100
Total possible outcomes = 100 = n(S)
Number of favorable outcomes for neither Re 1 nor Rs 5 coins = Number of favorable outcomes for Rs 2 coins = 50 = n(E)
Probability (neither Re 1 nor Rs 5 coin) = `(n(E))/(n(S)) = 50/100 = 1/2`
shaalaa.com
Is there an error in this question or solution?
