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Question
A bag contains twenty Rs 5 coins, fifty Rs 2 coins and thirty Re 1 coins. If it is equally likely that one of the coins will fall down when the bag is turned upside down, what is the probability that the coin will be a Re 1 coin?
Sum
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Solution
Total number of coins = 20 + 50 + 30 = 100
Total possible outcomes = 100 = n(S)
Number of favorable outcomes for Re 1 coins = 30 = n(E)
Probability (Re 1 coin) = `( n(E))/(n(S)) = 30/100 = 3/10 `
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