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Question
A bag contains 3 red, 3 white, 3 green, and 3 black balls. One ball is picked up from the bag at random. What is the probability that the ball drawn is:
a. white
b. not white.
Sum
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Solution
Let three red balls are R1 ,R2 ,R3
Three White balls are W1, W2, W3
Three green balls G1, G2,G3
Three black balls B1, B2, B3
S = {R1 ,R2 ,R3 , W1, W2, W3 , G1, G2,G3 , B1, B2, B3}
n(S) = 12
(a) Let A be the set of white balls
A = {W1, W2, W3}
n(A) = 3
P(A) = `("n"("A"))/("n"("S")) = 3/12 = 1/4`
(b) Let B be the set of not white balls.
B = {R1 ,R2 ,R3 ,G1, G2,G3 , B1, B2, B3}
n(B) = 9
P(A) =`("n"("B"))/("n"("S")) = 9/12 = 3/4`
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