Question

A bag contains 10 red balls, 16 white balls and 8 green balls. A ball is drawn out of the bag at random. What is the probability that the ball drawn will be neither red nor green?

Answer 1

Total number of possible outcomes = 10 + 16 + 8 = 34 balls 

n(S) = 34  

Favorable outcomes for neither a red nor a green ball = favourable outcomes for white ball

Number of favorable outcomes for white ball = 16 = n(E) 

Probability for not drawing a red or green ball = `(n(E))/(n(S)) = 16/34 = 8/17`