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Question
A 6.90 M solution of KOH in water contains 30% by weight of KOH. What is the density of the solution?
Numerical
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Solution
Given: Molarity (M) = 6.90 mol/L
Weight % of KOH = 30%
Molar mass of KOH = 56 g/mol
We need to find the density of the solution (in g/mL).
Let 1 L = 1000 mL of solution
Moles of KOH = 6.90 mol
Mass of KOH = 6.90 × 56 = 386.4 g
Weight % = `"Mass of solute"/"Mass of solution" xx 100`
`30 = 386.4/"Mass of solution" xx 100`
Mass of solution = `(386.4 xx 100)/30`
= 1288 g
Density = `"Mass of solution"/"Volume"`
= `1288/1000`
= 1.288 g/mL
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Chapter 2: Solutions - REVIEW EXERCISES [Page 67]
