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Question
A 2 kg collar M is attached to a spring and slides without friction in a vertical plane along the curved rod ABC as shown in figure. The spring has an un-deformed length of 100 mm and its stiffness k = 800N/m. If the collar is released from rest at A, determine its velocity
- as it passes through B.
- as it reaches C.

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Solution

It passes through B (A to B)
x1 = 250 − 100 = 150mm = 0.15
x2 = 200 − 100 = 100mm = 0.1
W . D = ΔK . E
`1/2 K(x_1^2 - x_2^2) + mgh = 1/2m(V_2^2 - V_1^2)`
`1/2 xx 800(0.15^2 - 0.1^2) + 2 xx 9.81 xx 0.2 = 1/2 xx 2 xx (V_2^2 - 0)`
V2 = 2.98m/s
It passes through C (A to C)
x1 = 250 − 100 = 150mm = 0.15
x2 = 150 − 100 = 50mm = 0.05m
W . D = ΔKE
`1/2 K(x_1^2 - x_2^2) + mgh = 1/2m(V_2^2 - V_1^2)`
`1/2 xx 800(0.15^2 - 0.05^2) = 1/2 xx 2 xx (V_2^2 - 0)`
V2 = 2.83m/s
Velocity of collar as it passes through B = 2.98 m/s
Velocity of collar as it passes through C = 2.83 m/s
