Question

`6x^2+x--12=0`

Answer 1

Given: 

`6x^2+x-12=0` 

`⇒ 6x^2+9x-8x-12=0` 

`⇒3x(2x+3)-4(2x+3)=0` 

`⇒(3x-4)(2x+3)=0` 

`⇒3x-4=0 or 2x+3=0` 

`⇒x=4/3  or  x=-3/2` 

Hence,` 4/3 and -3/2` are the root equation `6x^2+x-12=0`