Question

40g of ice at 0°C is used to bring down the temperature of a certain mass of water at 60°C to 10°C. Find the mass of water used.
[Specific heat capacity of water = 4200 J kg^-1 °C^-1]
[Specific latent heat of fusion of ice = 336 × 10³ J kg^-1]

Answer 1

Let mass of water used = m gm.

By principal of calorimetry,

Heat given = Heat taken

m₁c₁ΔQ₁ = mL + m₂c₂ΔQ₂ 

m × 4.2 × (60 - 10) = 40 × 336 + 40 × 4.2 × (10 - 0)

m × 4.2 × 50 = 40 × 336 + 1680

m = 72 gm