Question

`3x^2-2sqrt6x+2=0`

Answer 1

The given equation is `3x^2-2sqrt6x+2=0` 

Comparing it with `ax^2+bx+c=0`  

`a=3,b=-sqrt2 and c=2` 

∴ Discriminant, D=b^2-4ac=`(-2sqrt6)^2-4xx3xx2=24-24=0` 

So, the given equation has real roots.
Now, 

∴α= `(-b+sqrt(D))/(2a)=-(-2sqrt(6)+0)/(2xx3)=(2sqrt6)/6=sqrt6/3` 

β= `(-b-sqrt(D))/(2a)=-(-2sqrt(6))/(2xx3)=(2sqrt6)/6=sqrt6/3`  

Hence, `sqrt6/3` are the repeated of the given equation.