Question

`3sqrt7x^2+4x-sqrt7=0` 

 

Answer 1

Given: 

`3sqrt7x^2+4x-sqrt7=0` 

⇒`3sqrt7x^2+7x-3x-sqrt7=0` 

⇒`sqrt7x(3x+sqrt7)-1(3x+sqrt7)=0` 

⇒`(3x+sqrt7) (sqrt7-1)=0` 

⇒`3x+sqrt7`=0  or  `sqrt7x-1=0` 

⇒`x=-sqrt7/3`  or  `x=1/sqrt7=(1xxsqrt7)/(sqrt7xxsqrt7)=sqrt7/7` 

Hence, the roots of the equation are `-sqrt7/3` and `sqrt7/7`