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Question
300 cal. of heat is given to a heat engine and it rejects 225 cal. of heat. If source temperature is 227°C, then the temperature of sink will be ______ °C.
Options
102
103
106
105
MCQ
Fill in the Blanks
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Solution
300 cal. of heat is given to a heat engine and it rejects 225 cal. of heat. If source temperature is 227°C, then the temperature of sink will be 102 °C.
Explanation:
Assuming the engine to be Carnot engine
∴ `"Q"_"absorbed"/"Q"_"lost" = "T"_"source"/"T"_"sink"` ...(1)
On substituting values in equation (1)
`(300 "cal")/(225 "cal") = (500 "K")/("T"_"sink")`
`"T"_"sink" = 225/300xx500`
= 375 K
`"T"_"sink"` (in °C) = 375 - 273 = 102 °C
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Introduction of Thermodynamics
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