Question

`2x^2+x-6=0` 

 

Answer 1

We write, `x=4x-3x` as `2x^2xx(-6)=-12x^2=4xxx(-3x)` 

`∴ 2x^2+x-6=0` 

`⇒ 2x^2+4x-x-6=0 ` 

`⇒ 2x(x+2)-3(x+2)=0` 

`⇒(x+2)(2x-3)=0` 

`⇒x+2=0 or 2x-3=0` 

`⇒x=-2 or x=3/2` 

Hence, the roots of the given equation are `-2 and 3/2`