Question

`int_(-2)^3 dx/(x + 5)` = ______.

Options

• `-log(8/3)`

• `log(8/3)`

• `log(3/8)`

• `-log(3/8)`

• `3 log (3/8)`

• `-2 log (3/8)`

Answer 1

`int_(-2)^3 dx/(x + 5) = bbunderline(log(8/3))`

Explanation:

Let I = `int_(-2)^3 (1)/(x + 5)*dx`

= `[log |x + 5|]_(-2)^3`

= [log |3 + 5| – log |–2 + 5|]

= log 8 – log 3

∴ I = `log(8/3)`.