Question

1.56 g of sodium peroxide reacts with water according to the following equation:

\[\ce{2Na2O2 + 2H2O -> 4NaOH + O2}\]

Calculate the mass of oxygen liberated.

Answer 1

156 g of Na₂O₂ liberates O₂ = 32 g

∴ 1.56 g of Na₂O₂ liberates O₂

= `32/156 xx 1.56`

= 0.32 g