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Question
1500 families were surveyed and following data was recorded about their maids at homes
| Type of maids | Only part time | Only full time | Both |
| Number of families | 860 | 370 | 250 |
A family selected at random. Find the probability that the family selected has Part time maids
Sum
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Solution
Total number of families surveyed = 1500
n(S) = 1500
Number of families used maids = 860 + 370 + 250
= 1480
Number of families not using any maids = 1500 – 1480
= 20
Let E2 be the event of getting families use part time maids
n(E2) = 860
p(E2) = `("n"("E"_2))/("n"("S"))`
= `860/1500`
= `43/75`
Probability of getting part time maids = `43/75`
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Chapter 9: Probability - Exercise 9.2 [Page 302]
