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Maharashtra State BoardSSC (English Medium) 10th Standard

1, 7, 13, 19 ...... find 18th term of this A.P. - Algebra

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Question

1, 7, 13, 19 ...... find 18th term of this A.P.

Sum
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Solution

The given A.P. is 1, 7, 13, 19, ......

Here, a = 1, d = 7 – 1 = 6

Since tn = a + (n – 1)d,

t18 = 1 + (18 – 1)(6)

= 1 + 17(6)

= 1 + 102

= 103

∴ 18th term of the given A.P. is 103.

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Chapter 3: Arithmetic Progression - Q.2 (B)

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SCERT Maharashtra Algebra (Mathematics 1) [English] 10 Standard SSC
Chapter 3 Arithmetic Progression
Q.2 (B) | Q 7
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