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Solve the following quadratic equation by factorisation:
x2 + 3x - 18 = 0
Concept: undefined >> undefined
Solve the following quadratic equation by factorisation:
x2 - 3x - 10 = 0
Concept: undefined >> undefined
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Solve the following quadratic equation by factorisation:
9x2 - 3x - 2 = 0
Concept: undefined >> undefined
Solve the following quadratic equation by factorisation:
2x2 + ax - a2 = 0 where a ∈ R.
Concept: undefined >> undefined
Solve the following quadratic equation by factorisation method:
`x/(x + 1) + (x + 1)/x = (34)/(15') x ≠ 0, x ≠ -1`
Concept: undefined >> undefined
Solve the following quadratic equation by factorisation method:
`(x + 3)/(x - 2) - (1 - x)/x = (17)/(4)`.
Concept: undefined >> undefined
Solve the following quadratic equation:
4x2 - 4ax + (a2 - b2) = 0 where a , b ∈ R.
Concept: undefined >> undefined
Solve the following by reducing them to quadratic equations:
`((7y - 1)/y)^2 - 3 ((7y - 1)/y) - 18 = 0, y ≠ 0`
Concept: undefined >> undefined
Solve the following by reducing them to quadratic equations:
`sqrt(x/(1 -x)) + sqrt((1 - x)/x) = (13)/(6)`.
Concept: undefined >> undefined
Solve (x2 + 3x)2 - (x2 + 3x) -6 = 0.
Concept: undefined >> undefined
Solve the following by reducing them to quadratic form:
`sqrt(y + 1) + sqrt(2y - 5) = 3, y ∈ "R".`
Concept: undefined >> undefined
Solve the following by reducing them to quadratic form:
`sqrt(x^2 - 16) - (x - 4) = sqrt(x^2 - 5x + 4)`.
Concept: undefined >> undefined
Solve: x(x + 1) (x + 3) (x + 4) = 180.
Concept: undefined >> undefined
Solve the equation:
`6(x^2 + (1)/x^2) -25 (x - 1/x) + 12 = 0`.
Concept: undefined >> undefined
Solve for x:
`(x + 1/x)^2 - (3)/(2)(x - 1/x)-4` = 0.
Concept: undefined >> undefined
Solve the equation x4 + 2x3 - 13x2 + 2x + 1 = 0.
Concept: undefined >> undefined
In each of the following determine whether the given values are solutions of the equation or not.
3x2 - 2x - 1 = 0; x = 1
Concept: undefined >> undefined
In each of the following determine whether the given values are solutions of the equation or not.
x2 + 6x + 5 = 0; x = -1, x = -5
Concept: undefined >> undefined
In each of the following determine whether the given values are solutions of the equation or not
2x2 - 6x + 3 = 0; x = `(1)/(2)`
Concept: undefined >> undefined
In each of the following determine whether the given values are solutions of the equation or not.
6x2 - x - 2 = 0; x = `-(1)/(2), x = (2)/(3)`
Concept: undefined >> undefined
