Advertisements
Advertisements
प्रश्न
In each of the following determine whether the given values are solutions of the equation or not
2x2 - 6x + 3 = 0; x = `(1)/(2)`
Advertisements
उत्तर
Given equation is
2x2 - 6x + 3 = 0; x = `(1)/(2)`
Substitute x = `(1)/(2)` in L.H.S.
L.H.S. = `2 xx (1/2)^2 - 6 xx (1)/(2) + 3`
= `2 xx (1)/(4) - 3 + 3 = (1)/(2) ≠ 0`
Hence, x = `(1)/(2)` is not a solution ofthe given equation.
संबंधित प्रश्न
Solve the following quadratic equation by Factorisation method: x2 + 7x + 10 = 0
Solve the following quadratic equations by factorization:
4x2 + 5x = 0
Solve the following quadratic equations by factorization:
`7x + 3/x=35 3/5`
The length of a hall is 5 m more than its breadth. If the area of the floor of the hall is 84 m2, what are the length and breadth of the hall?
Solve each of the following equations by factorization :
`6/x=1+x`
Solve for x: `3x^2-2sqrt3x+2=0`
Solve the following quadratic equations by factorization:
\[3\left( \frac{7x + 1}{5x - 3} \right) - 4\left( \frac{5x - 3}{7x + 1} \right) = 11; x \neq \frac{3}{5}, - \frac{1}{7}\]
Solve the following equation: `1/("x" - 1) + 2/("x" - 1) = 6/"x" , (x ≠ 0)`
Solve the following quadratic equation using formula method only
6x2 + 7x - 10 = 0
Solve the following equation and give your answer up to two decimal places:
x2 − 5x − 10 = 0
