Definitions [4]
If y = f(u) is a differentiable function of u and u = g(x) is a differentiable function of x, then
\[\frac{dy}{dx}=\frac{dy}{du}\times\frac{du}{dx}\]
If y = f(x) is a differentiable function of x such that the inverse function x = f − 1(y) exists, then x is a differentiable function of
y and
\[\frac{dx}{dy}=\frac{1}{\frac{dy}{dx}},\frac{dy}{dx}\neq0\]
If x = f(t) and y = g(t) are differential functions of parameter ‘t’, then y is a differential function of x and
\[\begin{aligned}
\frac{dy}{dx} & =\frac{\frac{dy}{dt}}{\frac{dx}{dt}}, \\
\\
\frac{dx}{dt} & \neq0
\end{aligned}\]
If y = f(x) is a differentiable function of x, then its derivative f′(x) is also a function of x.
If this derivative f′(x) is again differentiable, its derivative is called the second derivative of f(x).
\[f^{\prime\prime}(x)\quad\mathrm{or}\quad\frac{d^2y}{dx^2}\]
If the second derivative is differentiable, its derivative is called the third derivative, denoted by:
\[f^{\prime\prime\prime}(x)\quad\mathrm{or}\quad\frac{d^3y}{dx^3}\]
Continuing this process, the derivative obtained after differentiating f(x) n times is called the nth derivative of f(x), and is denoted by:
\[f^{(n)}(x)\quad\mathrm{or}\quad\frac{d^ny}{dx^n}\]
These derivatives beyond the first derivative are called higher-order derivatives.
Formulae [8]
1. Sum Rule:
\[y=u\pm v\] then \[\frac{dy}{dx}=\frac{du}{dx}\pm\frac{dv}{dx}\]
2. Product Rule:
\[y=uv\] then \[\frac{dy}{dx}=u\frac{d\nu}{dx}+\nu\frac{du}{dx}\]
3. Quotient Rule:
\[y=\frac{u}{v}\] where v ≠ 0 then \[\frac{dy}{dx}=\frac{\nu\frac{du}{dx}-u\frac{d\nu}{dx}}{\nu^{2}}\]
4. Difference Rule:
y = u − v then \[\frac{dy}{dx}=\frac{du}{dx}-\frac{dv}{dx}\]
5. Constant Multiple:
y = k. u then \[\frac{dy}{dx}=k.\frac{du}{dx}\], k constant.
| y = f(x) | \[\frac{dy}{dx}=f^{\prime}(x)\] |
|---|---|
| c (Constant) | 0 |
| \[X^{n}\] | \[nx^{n-1}\] |
| \[\frac{1}{x}\] | \[-\frac{1}{x^2}\] |
| \[\frac{1}{x^n}\] | \[-\frac{n}{x^{n+1}}\] |
| \[\sqrt{x}\] | \[\frac{1}{2\sqrt{x}}\] |
| sin x | cos x |
| cos x | -sin x |
| tan x | sec2 x |
| cot x | -cosec2 x |
| sec x | sec x.tan x |
| cosec x | -cosec x cot x |
| \[e^{X}\] | \[e^{X}\] |
| \[a^{X}\] | \[a^xloga\] |
| log x | \[\frac{1}{x}\] |
| \[\log_{a}x\] | \[\frac{1}{x\log a}\] |
| Type of Function | Derivative |
|---|---|
| \[a^{x}\] | \[a^x\log a\] |
| \[e^{x}\] | \[e^{x}\] |
| \[x^{x}\] | \[x^x(1+\log x)\] |
| \[x^{a}\](a constant) | \[ax^{a-1}\] |
| \[a^{f(x)}\] | \[a^{f(x)}\log a\cdot f^{\prime}(x)\] |
| Given | Formula / Result |
|---|---|
| x = f(t), ; y = g(t) | Parametric form |
| First derivative | \[\frac{dy}{dx}=\frac{\frac{dy}{dt}}{\frac{dx}{dt}}\] |
| Condition | \[\frac{dx}{dt}\neq0\] |
| Second derivative | \[\frac{d^2y}{dx^2}=\frac{d}{dt}\left(\frac{dy}{dx}\right)/\frac{dx}{dt}\] |
If: u = f(x),v = g(x)
Then: \[\frac{du}{dv}=\frac{du/dx}{dv/dx}\]
General implicit form: F(x,y) = 0
\[x^my^n=(x+y)^{m+n}\]
\[\frac{dy}{dx}=\frac{y}{x}\]
| Expression | Derivative |
|---|---|
| \[y^{n}\] | \[ny^{n-1}\frac{dy}{dx}\] |
| f (y) | \[f^{\prime}(y)\frac{dy}{dx}\] |
| sin y | \[\cos y\frac{dy}{dx}\] |
| cos y | \[-\sin y\frac{dy}{dx}\] |
| \[e^{y}\] | \[e^y\frac{dy}{dx}\] |
| log y | \[\frac{1}{y}\frac{dy}{dx}\] |
| y | dy/dx |
|---|---|
| \[[f(x)]^{n}\] | \[n\left[f(x)\right]^{n-1}\cdot f^{\prime}(x)\] |
| \[\sqrt{f(x)}\] | \[\frac{f^{\prime}(x)}{2\sqrt{f(x)}}\] |
| \[\frac{1}{[f(x)]^{n}}\] | \[-\frac{n\cdot f^{\prime}(x)}{[f(x)]^{n+1}}\] |
| sin [f(x)] | \[\cos[f(x)]\cdot f^{\prime}(x)\] |
| cos [f(x)] | \[-\sin\left[f(x)\right]\cdot f^{\prime}(x)\] |
| tan [f(x)] | \[\sec^2[f(x)]\cdot f^{\prime}(x)\] |
| sec [f(x)] | \[\sec\left[f(x)\right]\cdot\tan\left[f(x)\right]\cdot f^{\prime}(x)\] |
| cot [f(x)] | \[-\operatorname{cosec}^2[f(x)]\cdot f^{\prime}(x)\] |
| cosec [f(x)] | \[-\operatorname{cosec}\left[f(x)\right]\cdot\cot\left[f(x)\right]\cdot f^{\prime}(x)\] |
| \[a^{f(x)}\] | \[a^{f(x)}\log a\cdot f^{\prime}(x)\] |
| \[e^{f(x)}\] | \[e^{f(x)}\cdot f^{\prime}(x)\] |
| log [f(x)] | \[\frac{f^\prime(x)}{f(x)}\] |
| \[\log_{a}[f(x)]\] | \[\frac{f^{\prime}(x)}{f(x)\log a}\] |
| y | dy/dx | Conditions |
|---|---|---|
| \[\sin^{-1}x\] | \[\frac{1}{\sqrt{1-x^2}},|x|<1\] | −1 ≤ x ≤ 1 \[-\frac{\pi}{2}\leq y\leq\frac{\pi}{2}\] |
| \[\cos^{-1}x\] | \[-\frac{1}{\sqrt{1-x^{2}}},|x|<1\] | −1 ≤ x ≤ 1 0 ≤ y ≤ π |
| \[\tan^{-1}x\] | \[\frac{1}{1+x^2}\] | x ∈ R \[-\frac{\pi}{2}<y<\frac{\pi}{2}\] |
| \[\cot^{-1}x\] | \[-\frac{1}{1+x^2}\] | x ∈ R 0 < y < π |
| \[\sec^{-1}x\] | \[\frac{1}{x\sqrt{x^{2}-1}}\quad\mathrm{for}x>1\] | 0 ≤ y ≤ π |
| \[-\frac{1}{x\sqrt{x^2-1}}\mathrm{~for~}x<-1\] | \[y\neq\frac{\pi}{2}\] | |
| \[cosec^{-1}x\] | \[-\frac{1}{x\sqrt{x^{2}-1}}\mathrm{for}x>1\] | \[-\frac{\pi}{2}\leq y\leq\frac{\pi}{2}\] |
| \[{\frac{1}{x{\sqrt{x^{2}-1}}}}\quad{\mathrm{for}}x<-1\] | \[y\neq0\] |
Theorems and Laws [1]
If cos y = x cos (a + y), with cos a ≠ ± 1, prove that `dy/dx = cos^2(a+y)/(sin a)`.
cos y = x cos (a + y)
∴ x = `(cos y)/(cos (a + y))`
On differentiating with respect to y,
`cos (a + y) d/dy cos y - cos y d/dy`
`therefore dx/dy = (cos (a + y))/(cos^2 (a + y))`
`= (- sin y cos (a + y) + cos y sin (a + y))/(cos^2 (a + y))`
`= (sin (a + y) cos y - cos (a + y) sin y)/(cos^2 (a + y))`
`= (sin (a + y - y))/(cos^2 (a + y))` ...[∵ sin (A − B) = sin A cos B − cos A sin B]
`= (sin a)/(cos^2 (a + y))`
`therefore dy/dx = (cos^2 (a + y))/(sin a)`
Key Points
1. Elasticity of Demand
\[\eta=-\frac{P}{D}\cdot\frac{dD}{dP}\]
2. Marginal Revenue & Elasticity Relation
\[R_m=R_A\left(1-\frac{1}{\eta}\right)\]
3. Propensity to Consume & Save
MPC + MPS = 1
APC + APS = 1
Important Questions [19]
- If y is a function of x and log (x + y) = 2xy, then the value of y'(0) = ______.
- Solve x+ydydx=sec(x2+y2)
- If Y = Tan 2 ( Log X 3 ) , Find D Y D X
- If y = sec (tan^−1x), then dy/dx at x = 1 is ______.
- Find dy/dx, if xsqrt(x) + ysqrt(y) = asqrt(a).
- Find dy/dx, if sqrt(x) + sqrt(y) = sqrt(a).
- If x = f(t) and y = g(t) are differentiable functions of t so that y is a differentiable function of x and dxdt ≠ 0 then dydx=dydtdxd. Hence find dydx if x = sin t and y = cost
- If ∫dx4x2-1 = A log (2x-12x+1) + c, then A = ______.
- Evaluate: ∫logxdx
- If log10(x3-y3x3+y3) = 2, show that dydx=-99x2101y2.
- Find dydx, if y = (log x)x.
- Find dy/dx if x sin y + y sin x = 0.
- If y = emtan-1x then show that (1+x2)d2ydx2+(2x-m)dydx = 0
- If xpyq = (x + y)p+q then Prove that dydx=yx
- If y = tanx+tanx+tanx+....+ ∞, then show that dydx=sec2x2y-1. Find dydx at x = 0.
- If y=e^(ax) ,show that x dy/dx=y logy
- If x = f(t) and y = g(t) are differentiable functions of t, so that y is function of x and dxdt≠0 then prove that dydx=dydtdxdt. Hence find dydx, if x = at2, y = 2at.
- If y = sin–1x, then show that (1-x2)d2ydx2-x⋅dydx = 0
- If y = cos(m cos–1x), then show that (1-x2)d2ydx2-xdydx+m2y = 0
