Definitions [12]
A differential equation of the form \[\frac{dy}{dx}=\frac{f(x,y)}{\phi(x,y)}\] where f(x,y) and ϕ(x,y) are homogeneous functions of the same degree, is called a homogeneous differential equation.
A differential equation is an equation that involves independent and dependent variables and their derivatives.
The order of a differential equation is the order of the highest derivative occurring in it.
The degree of a differential equation is the degree of the derivative of the highest order occurring in it after the equation is freed from radical signs and fractions in the derivative.
General Solution
-
A solution containing arbitrary constants equal to the order of the differential equation is called the general solution.
Particular Solution
-
Solutions obtained by giving particular values to the arbitrary constants in the general solution are called particular solutions.
A differential equation in which the variables can be separated is of the form
\[f(x)dx+\phi(y)dy=0\]
The factor e∫P dx on multiplying by which the left-hand side of the differential equation\[\frac{dy}{dx}+Py=Q\] becomes the differential coefficient of a function of x and y, is called the integrating factor of the differential equation.
General Solution: \[y\cdot\mathrm{I.F.}=\int Q\cdot\mathrm{I.F.}dx+c\]
A function f(x,y) is called a homogeneous function of degree n if the degree of each term is n.
A differential equation is non-linear if any one of the following holds:
-
The degree is more than one
-
Any differential coefficient has an exponent of more than one
-
Exponent of the dependent variable is more than one
-
Products containing the dependent variable and its differential coefficients are present
A solution or an integral of a differential equation is a function of the form y = f(x) which satisfies the given differential equation.
A first-order differential equation, along with an initial condition, is called an initial value problem.
A differential equation is said to be linear·if the dependent variable and its differential coefficients occur in it in the first degree only and are not multiplied together.
General Form: \[\frac{dy}{dx}+Py=Q\]
where P and Q are functions of x.
Theorems and Laws [1]
Prove that:
`int_0^(2a)f(x)dx = int_0^af(x)dx + int_0^af(2a - x)dx`
Since ‘a’ lies between 0 and 2a,
we have
`int_0^(2a)f(x)dx=int_0^af(x)dx+int_a^(2a)f(x)dx, .......(byint_a^bf(x)dx=int_a^cf(x)dx+int_c^bf(x)dx)`
`=I_1+I_2` ........................(say)
`I_2 = int_a^(2a)f(x)dx`
Put x = 2a − t
Therefore, dx = −dt
When x = a, 2a − t = a
t = a
When x = 2a, 2a − t = 2a
t = 0
`I_2 = int_0^(2a) f(x) dx = int_a^0 f(2a - t) (-dt)`
`= -int_a^0 f(2a - t)dt = int_0^a f(2a - t)dt ...................... (By int_a^b f(x)dx = -int_b^a f(x)dx)`
`=int_0^a f(2a - x)dx ..............(By int_a^b f(X)dx = int_a^b f(t)dt)`
`int_0^(2a) f(x)dx = int_0^a f(x)dx + int_0^a f(2a - x)dx`
`= int_0^a [f(x) + f(2a - x)]dx`
To show that:
`int_0^pi sin x dx = 2 int_0^(pi/2) sin x dx`
We use the proven property by setting f(x) = sin x and 2a = π, which means a = `pi/2`.
The property tells us that:
`int_0^pi sin x dx = int_0^(pi/2) sin x dx + int_0^(pi/2) sin (pi - x) dx`
Knowing the trigonometric identity sin (π - x) = sin x, the equation simplifies to:
`int_0^pi sin x dx = 2 int_0^(pi/2) sin x dx`
This directly applies the property to the integral of sin x over [0, π] to show it equals twice the integral of sin x over `[0, pi/2]`, demonstrating the utility of this property in simplifying integrals with symmetric functions over specific intervals.
Key Points
-
Put y = vx
-
Separate the variables v and x
-
Integrate both sides
-
Replace v by \[\frac{y}{x}\]
- Radioactive Decay: \[x=x_0e^{-kt}\]
-
Half-Life Formula: \[k=\frac{\ln2}{T}\]
-
Newton’s Law of Cooling: \[\theta=\theta_0+(\theta_1-\theta_0)e^{-kt}\]
- Population Growth: \[P=ae^{kt}\]
-
Write the equation in the form
\[\frac{dy}{dx}+Py=Q\] -
Find the integrating factor
\[\mathrm{I.F.}=e^{\int Pdx}\] -
Multiply the entire equation by I.F.
-
Integrate both sides w.r.t x
-
Obtain
\[y(\mathrm{I.F.})=\int Q(\mathrm{I.F.})dx+c\]
Important Questions [21]
- The differential equation ydydx+x=0 represents family of ______.
- Solve the differential equation ydydx+x = 0
- Prove that: ∫02af(x)dx=∫0af(x)dx+∫0af(2a-x)dx
- Order and Degree of the Differential Equation
- State the degree of differential equation 𝑒𝑑𝑦/𝑑𝑥 +𝑑𝑦/𝑑𝑥 = x
- Write the degree of the differential equation (y''')2 + 3(y") + 3xy' + 5y = 0
- The integrating factor of linear differential equation xdydx+2y=x2logx is ______.
- A particle is moving along the X-axis. Its acceleration at time t is proportional to its velocity at that time. Find the differential equation of the motion of the particle.
- Form the differential equation of all lines which makes intercept 3 on x-axis.
- Solve the following differential equation: cos x . cos y dy − sin x . sin y dx = 0
- Obtain the differential equation by eliminating the arbitrary constants from the following equation: y = A cos (log x) + B sin (log x)
- Solve the differential equation (x2 + y2)dx- 2xydy = 0
- Solve the following differential equation: x⋅dydx-y+x⋅sin(yx)=0
- Solve the following differential equation: x^2 dy/dx = x^2 + xy + y^2
- Solve the following differential equation: dr + (2r cotθ + sin2θ)dθ = 0
- The slope of the tangent to the curve x = sin θ and y = cos 2θ at θ = ππ6 is ______.
- The solution of the differential equation dxdt=xlogxt is ______.
- Solve the following differential equation: dy/dx + y/x = x^3 – 3
- If a body cools from 80°C to 50°C at room temperature of 25°C in 30 minutes, find the temperature of the body after 1 hour.
- Find the particular solution of the differential equation dydx = e2y cos x, when x = ππ6, y = 0
- Solve: 1+dydx=cosec(x+y); put x + y = u.
