मराठी

Write the Value of Cos−1 - Mathematics

Advertisements
Advertisements

प्रश्न

Write the value of cos−1 \[\left( \tan\frac{3\pi}{4} \right)\]

Advertisements

उत्तर

We have

\[\cos^{- 1} \left( \tan\frac{3\pi}{4} \right) = \cos^{- 1} \left\{ - \tan\left( \pi - \frac{3\pi}{4} \right) \right\} \left[ \because \tan\left( \pi - x \right) = - \tan{x} \right]\]
\[ = \cos^{- 1} \left\{ \tan\left( - \frac{\pi}{4} \right) \right\}\]
\[ = \cos^{- 1} \left\{ - \tan\left( \frac{\pi}{4} \right) \right\}\]
\[ = \cos^{- 1} \left( - 1 \right)\]
\[ = \cos^{- 1} \left( cos\pi \right) \left[ \because cos\pi = - 1 \right]\]
\[ = \pi\]

∴ \[\cos^{- 1} \left( \tan\frac{3\pi}{4} \right) = \pi\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११७]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 19 | पृष्ठ ११७

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

 

Show that:

`2 sin^-1 (3/5)-tan^-1 (17/31)=pi/4`

 

 

Prove that

`tan^(-1) [(sqrt(1+x)-sqrt(1-x))/(sqrt(1+x)+sqrt(1-x))]=pi/4-1/2 cos^(-1)x,-1/sqrt2<=x<=1`


`sin^-1(sin3)`


Evaluate the following:

`cos^-1{cos  (5pi)/4}`


Evaluate the following:

`cos^-1(cos4)`


Evaluate the following:

`tan^-1(tan  (9pi)/4)`


Evaluate the following:

`cot^-1(cot  pi/3)`


Write the following in the simplest form:

`tan^-1{sqrt(1+x^2)-x},x in R`


Evaluate the following:

`sin(sin^-1  7/25)`

 


Evaluate:

`cos{sin^-1(-7/25)}`


If `(sin^-1x)^2+(cos^-1x)^2=(17pi^2)/36,`  Find x


`sin^-1x=pi/6+cos^-1x`


Find the value of `tan^-1  (x/y)-tan^-1((x-y)/(x+y))`


Solve the following equation for x:

`tan^-1  2x+tan^-1  3x = npi+(3pi)/4`


Solve the following equation for x:

`tan^-1((1-x)/(1+x))-1/2 tan^-1x` = 0, where x > 0


Solve the following equation for x:

`tan^-1((x-2)/(x-4))+tan^-1((x+2)/(x+4))=pi/4`


Sum the following series:

`tan^-1  1/3+tan^-1  2/9+tan^-1  4/33+...+tan^-1  (2^(n-1))/(1+2^(2n-1))`


`(9pi)/8-9/4sin^-1  1/3=9/4sin^-1  (2sqrt2)/3`


Solve `cos^-1sqrt3x+cos^-1x=pi/2`


Prove that:

`2sin^-1  3/5=tan^-1  24/7`


Solve the following equation for x:

`tan^-1((2x)/(1-x^2))+cot^-1((1-x^2)/(2x))=(2pi)/3,x>0`


Write the difference between maximum and minimum values of  sin−1 x for x ∈ [− 1, 1].


Write the value of tan1 x + tan−1 `(1/x)`  for x < 0.


Write the value of cos−1 (cos 1540°).


Evaluate sin

\[\left( \frac{1}{2} \cos^{- 1} \frac{4}{5} \right)\]


Write the value of sin \[\left\{ \frac{\pi}{3} - \sin^{- 1} \left( - \frac{1}{2} \right) \right\}\]


Write the value of \[\cos\left( \sin^{- 1} x + \cos^{- 1} x \right), \left| x \right| \leq 1\]


Wnte the value of the expression \[\tan\left( \frac{\sin^{- 1} x + \cos^{- 1} x}{2} \right), \text { when } x = \frac{\sqrt{3}}{2}\]


Write the value of  `cot^-1(-x)`  for all `x in R` in terms of `cot^-1(x)`


Wnte the value of\[\cos\left( \frac{\tan^{- 1} x + \cot^{- 1} x}{3} \right), \text{ when } x = - \frac{1}{\sqrt{3}}\]


Find the value of \[\cos^{- 1} \left( \cos\frac{13\pi}{6} \right)\]


Find the value of \[\tan^{- 1} \left( \tan\frac{9\pi}{8} \right)\]


If α = \[\tan^{- 1} \left( \tan\frac{5\pi}{4} \right) \text{ and }\beta = \tan^{- 1} \left( - \tan\frac{2\pi}{3} \right)\] , then

 

\[\text{ If }\cos^{- 1} \frac{x}{3} + \cos^{- 1} \frac{y}{2} = \frac{\theta}{2}, \text{ then }4 x^2 - 12xy \cos\frac{\theta}{2} + 9 y^2 =\]


If α = \[\tan^{- 1} \left( \frac{\sqrt{3}x}{2y - x} \right), \beta = \tan^{- 1} \left( \frac{2x - y}{\sqrt{3}y} \right),\] 
 then α − β =


\[\cot\left( \frac{\pi}{4} - 2 \cot^{- 1} 3 \right) =\] 

 


Prove that : \[\cot^{- 1} \frac{\sqrt{1 + \sin x} + \sqrt{1 - \sin x}}{\sqrt{1 + \sin x} - \sqrt{1 - \sin x}} = \frac{x}{2}, 0 < x < \frac{\pi}{2}\] .


If \[\tan^{- 1} \left( \frac{1}{1 + 1 . 2} \right) + \tan^{- 1} \left( \frac{1}{1 + 2 . 3} \right) + . . . + \tan^{- 1} \left( \frac{1}{1 + n . \left( n + 1 \right)} \right) = \tan^{- 1} \theta\] , then find the value of θ.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×