Advertisements
Advertisements
प्रश्न
Write in the expanded form (a2 + b2 + c2 )2
Advertisements
उत्तर
We have
(a2 + b2 + c2 )2 = (a2 )2 + (b2 )2 + (c2 )2 + 2a2b2 + 2b2c2 + 2a2c2
∵ (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
= a4 + b4 + c4 + 2a2b2 + 2b2c2 + 2a2c2
∴ (a2 + b2 + c2 )2 = a4 + b4 + c4 + 2a2b2 + 2b2c2 + 2a2c2
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
(3 – 2x) (3 + 2x)
Factorise the following:
27 – 125a3 – 135a + 225a2
If x + y + z = 0, show that x3 + y3 + z3 = 3xyz.
Evaluate the following using identities:
`(2x+ 1/x)^2`
Evaluate the following using identities:
(1.5x2 − 0.3y2) (1.5x2 + 0.3y2)
Write in the expanded form:
`(2 + x - 2y)^2`
Write in the expanded form: (-2x + 3y + 2z)2
Evaluate of the following:
(103)3
If \[x + \frac{1}{x} = 3\], calculate \[x^2 + \frac{1}{x^2}, x^3 + \frac{1}{x^3}\] and \[x^4 + \frac{1}{x^4}\]
Simplify of the following:
\[\left( x + \frac{2}{x} \right)^3 + \left( x - \frac{2}{x} \right)^3\]
If \[x^4 + \frac{1}{x^4} = 119\] , find the value of \[x^3 - \frac{1}{x^3}\]
If x = 3 and y = − 1, find the values of the following using in identify:
(9y2 − 4x2) (81y4 +36x2y2 + 16x4)
If a2 + b2 + c2 − ab − bc − ca =0, then
Use the direct method to evaluate :
(0.5−2a) (0.5+2a)
Expand the following:
`(2"a" + 1/(2"a"))^2`
Find the squares of the following:
(2a + 3b - 4c)
Evaluate, using (a + b)(a - b)= a2 - b2.
399 x 401
Simplify:
(3a + 2b - c)(9a2 + 4b2 + c2 - 6ab + 2bc +3ca)
Expand the following:
(4a – b + 2c)2
Expand the following:
`(4 - 1/(3x))^3`
