Advertisements
Advertisements
प्रश्न
Find the following product:
\[\left( \frac{3}{x} - \frac{5}{y} \right) \left( \frac{9}{x^2} + \frac{25}{y^2} + \frac{15}{xy} \right)\]
Advertisements
उत्तर
Given \[\left( \frac{3}{x} - \frac{5}{y} \right) \left( \frac{9}{x^2} + \frac{25}{y^2} + \frac{15}{xy} \right)\]
We shall use the identity `(a-b)(a^2 + ab+ b^2) = a^3 - b^3`
We can rearrange the ` (3/5 - 5/y) (9^2/x^2 + 25/y^2 + 15/(xy))`as
` = ((3/x - 5/y) ((3/x)^2 + (5/y)^2 + (3/x)(5/y))`
` = (3/x)^3 - (5/y)^3 `
\[= \left( \frac{3}{x} \right) \times \left( \frac{3}{x} \right) \times \left( \frac{3}{x} \right) - \left( \frac{5}{y} \right) \times \left( \frac{5}{y} \right) \times \left( \frac{5}{y} \right)\]
\[ = \frac{27}{x^3} - \frac{125}{y^3}\]
Hence the Product value of `(3/x - 5/y) (9^2/x^2 + 25/y^3 + 15/(xy))`is `27/x^3 - 125/y^3`.
APPEARS IN
संबंधित प्रश्न
Factorise the following:
64m3 – 343n3
Without actually calculating the cubes, find the value of the following:
(28)3 + (–15)3 + (–13)3
If 9x2 + 25y2 = 181 and xy = −6, find the value of 3x + 5y
Simplify (a + b + c)2 + (a - b + c)2
If x = 3 and y = − 1, find the values of the following using in identify:
(9y2 − 4x2) (81y4 +36x2y2 + 16x4)
Evaluate:
253 − 753 + 503
Mark the correct alternative in each of the following:
If \[x + \frac{1}{x} = 5\] then \[x^2 + \frac{1}{x^2} = \]
(a − b)3 + (b − c)3 + (c − a)3 =
75 × 75 + 2 × 75 × 25 + 25 × 25 is equal to
Use identities to evaluate : (97)2
Use identities to evaluate : (998)2
If a + b = 7 and ab = 10; find a - b.
Expand the following:
(a + 3b)2
Expand the following:
`(2"a" + 1/(2"a"))^2`
If `"a" + 1/"a" = 6;`find `"a"^2 - 1/"a"^2`
If `x + (1)/x = 3`; find `x^2 + (1)/x^2`
If `"a"^2 - 7"a" + 1` = 0 and a = ≠ 0, find :
`"a"^2 + (1)/"a"^2`
If `"p" + (1)/"p" = 6`; find : `"p"^4 + (1)/"p"^4`
Simplify:
(2x + y)(4x2 - 2xy + y2)
Simplify:
(x + 2y + 3z)(x2 + 4y2 + 9z2 - 2xy - 6yz - 3zx)
