Evaluate: (6 − 5xy) (6 + 5xy)

Evaluate: (6 − 5xy) (6 + 5xy)

बेरीज

(6 − 5xy) (6 + 5xy)

= (6)²− (5xy)²

= 36 − 25x²y² .........[ ∵ (a − b) (a + b) = a²b²]

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पाठ 12: Identities - Exercise 12 (D) [पृष्ठ १५५]

पाठ 12 Identities
Exercise 12 (D) | Q 2.03 | पृष्ठ १५५

Evaluate the following product without multiplying directly:

104 × 96

if `x^2 + 1/x^2 = 79` Find the value of `x + 1/x`

Simplify the following products:

`(x^3 - 3x^2 - x)(x^2 - 3x + 1)`

Simplify the following expressions:

`(x^2 - x + 1)^2 - (x^2 + x + 1)^2`

Find the value of 27x³ + 8y³, if 3x + 2y = 20 and xy = \[\frac{14}{9}\]

If \[x - \frac{1}{x} = \frac{1}{2}\],then write the value of \[4 x^2 + \frac{4}{x^2}\]

Evalute : `((2x)/7 - (7y)/4)^2`

If x + y = `7/2 "and xy" =5/2`; find: x - y and x² - y²

If a - b = 10 and ab = 11; find a + b.

If a² - 3a - 1 = 0 and a ≠ 0, find : `"a" + (1)/"a"`