Advertisements
Advertisements
प्रश्न
If `"a"^2 - 7"a" + 1` = 0 and a = ≠ 0, find :
`"a" + (1)/"a"`
बेरीज
Advertisements
उत्तर
Dividing the given equation by a, we get:
`"a"^2/"a" - (7"a")/"a" + 1/"a" = 0, "a" - 7 + 1/"a" = 0`
⇒ `"a" + (1)/"a"` = 7.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Expand the following, using suitable identity:
(–2x + 3y + 2z)2
Evaluate the following using identities:
(1.5x2 − 0.3y2) (1.5x2 + 0.3y2)
If \[x^4 + \frac{1}{x^4} = 119\] , find the value of \[x^3 - \frac{1}{x^3}\]
Find the following product:
\[\left( \frac{x}{2} + 2y \right) \left( \frac{x^2}{4} - xy + 4 y^2 \right)\]
If a + b = 6 and ab = 20, find the value of a3 − b3
Evaluate:
\[\left( \frac{1}{2} \right)^3 + \left( \frac{1}{3} \right)^3 - \left( \frac{5}{6} \right)^3\]
Evaluate:
(0.2)3 − (0.3)3 + (0.1)3
Use identities to evaluate : (101)2
Evaluate : (4a +3b)2 - (4a - 3b)2 + 48ab.
Factorise the following:
9y2 – 66yz + 121z2
