Advertisements
Advertisements
प्रश्न
Why is boiling point of 1 M NaCl solution more than that of 1 M glucose solution?
Advertisements
उत्तर
Because the van't Hoff factor of 1 M NaCl (2) solution is bigger than that of 1 M glucose (1) solution, boiling point is directly proportional to molality and van't Hoff factor. As a result, the boiling point of 1 M NaCl is higher than that of 1 M glucose solution.
APPEARS IN
संबंधित प्रश्न
Define the term abnormal molar mass.
How will you convert the following in not more than two steps:
Acetophenone to Benzoic acid
Give reasons for the following
Elevation of the boiling point of 1 M KCl solution is nearly double than that of 1 M sugar solution.
The van’t Hoff factor (i) accounts for ____________.
The values of Van’t Hoff factors for KCl, NaCl and K2SO4, respectively, are ______.
Van't Hoff factor I is given by expression.
What is the expected each water van't Hoff factor for and K4[F4(CN6)] when it completely dissociated in waters.
Maximum lowering of vapour pressure is observed in the case of ______.
Consider the reaction
\[\begin{bmatrix}\begin{array}{cc}
\phantom{.......}\ce{CH3}\\
\phantom{....}|\\
\ce{CH3CH2CH2 - \overset{⊕}{N} - CH2CH3}\\
\phantom{....}|\\
\phantom{.......}\ce{CH3}
\end{array}\end{bmatrix}\]\[\ce{OH^- ->[Heat] ?}\]
Which of the following is formed in a major amount?
Why is the value of van't Hoff factor for ethanoic acid in benzene close to 0.5?
