मराठी

Why is boiling point of 1 M NaCl solution more than that of 1 M glucose solution? - Chemistry

Advertisements
Advertisements

प्रश्न

Why is boiling point of 1 M NaCl solution more than that of 1 M glucose solution?

टीपा लिहा
Advertisements

उत्तर

Because the van't Hoff factor of 1 M NaCl (2) solution is bigger than that of 1 M glucose (1) solution, boiling point is directly proportional to molality and van't Hoff factor. As a result, the boiling point of 1 M NaCl is higher than that of 1 M glucose solution.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2022-2023 (March) Delhi Set 1

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Derive van’t Hoff general solution equation.


19.5 g of CH2FCOOH is dissolved in 500 g of water. The depression in the freezing point of water observed is 1.0°C. Calculate the van’t Hoff factor and dissociation constant of fluoroacetic acid.


How van’t Hoff factor is related to the degree of dissociation?


The freezing point depression constant for water is 1.86° K Kg mol-1. If 5 g Na2SO4 is dissolved in 45 g water, the depression in freezing point is 3.64°C. The Vant Hoff factor for Na2SO4 is ______.


Van't Hoff factor I is given by expression.


Maximum lowering of vapour pressure is observed in the case of ______.


Geraniol, a volatile organic compound, is a component of rose oil. The density of the vapour is 0.46 g L–1 at 257°C and 100 mm Hg. The molar mass of geraniol is ______ g mol–1. (Nearest Integer)

[Given: R = 0.082 L atm K–1 mol–1]


The degree of dissociation of Ca(NO3)2 in a dilute aqueous solution containing 7 g of the salt per 100 g of water at 100°C is 70%. If the vapour pressure of water at 100°C is 760 mm. The vapour pressure of the solution is ______ mm.


Consider the reaction

\[\begin{bmatrix}\begin{array}{cc}
\phantom{.......}\ce{CH3}\\
\phantom{....}|\\
\ce{CH3CH2CH2 - \overset{⊕}{N} - CH2CH3}\\
\phantom{....}|\\
\phantom{.......}\ce{CH3}
\end{array}\end{bmatrix}\]\[\ce{OH^- ->[Heat] ?}\]

Which of the following is formed in a major amount?


When 19.5 g of F – CH2 – COOH (Molar mass = 78 g mol−1), is dissolved in 500 g of water, the depression in freezing point is observed to be 1°C. Calculate the degree of dissociation of F – CH2 – COOH.

[Given: Kf for water = 1.86 K kg mol−1]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×