मराठी

What type of deviation is shown by a mixture of ethanol and acetone? Give reason.

Advertisements
Advertisements

प्रश्न

What type of deviation is shown by a mixture of ethanol and acetone? Give reason.

What type of deviation from Raoult’s law is shown by ethanol and acetone mixture? Give reason.

कारण सांगा
Advertisements

उत्तर १

Ethanol and acetone show +ve deviation because both are non-polar compounds and after mixing, the force of attraction decreases.

Particle force of attraction > Unlike particle force of attraction

shaalaa.com

उत्तर २

A mixture of ethanol and acetone shows positive deviation from Raoult's Law. Pure ethanol possesses hydrogen bonding. Introduction of acetone between the molecules of ethanol results in breaking of some of these hydrogen bonds. Due to weakening of interactions, the solution shows positive deviation from Raoult’s law.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2013-2014 (March) All India Set 2

संबंधित प्रश्‍न

Vapour pressure of pure water at 298 K is 23.8 mm Hg. 50 g of urea (NH2CONH2) is dissolved in 850 g of water. Calculate the vapour pressure of water for this solution and its relative lowering.


An aqueous solution of 2% non-volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molar mass of the solute?


Calculate the mass of a non-volatile solute (molar mass 40 g mol−1) which should be dissolved in 114 g octane to reduce its vapour pressure to 80%.


A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate:

  1. molar mass of the solute.
  2. vapour pressure of water at 298 K.

What type of azeotrope is formed by positive deviation from Raoult’s law?


Raoult’s law states that for a solution of volatile liquids the partial pressure of each component in the solution is ____________.


Using Raoult’s law explain how the total vapour pressure over the solution is related to mole fraction of components in the following solutions.

\[\ce{CHCl3(l) and CH2Cl2(l)}\]


Two liquids X and Y form an ideal solution. The mixture has a vapour pressure of 400 mm at 300 K when mixed in the molar ratio of 1 : 1 and a vapour pressure of 350 mm when mixed in the molar ratio of 1 : 2 at the same temperature. The vapour pressures of the two pure liquids X and Y respectively are ______.


The correct option for the value of vapour pressure of a solution at 45°C with benzene to octane in a molar ratio of 3 : 2 is

[At 45°C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]


An azeotropic mixture of two liquids will have a boiling point lower than either of the two liquids when it ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×