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प्रश्न
Water falls from a height of 50 m. Calculate the rise in the temperature of water when it strikes the bottom.
(g = 10 ms-2; Specific heat capacity of water = 4200 J / kg°C)
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उत्तर
If the whole of the energy due to the fall of water changes into heat energy, and 0°C be the rice in the temperature of water, then
mgh = ms θ°
Or m × 10 × 50 = m × 4200 × θ°
Or θ°, i.e. rise in temperature of water = `("m" xx 10 xx 50)/("m" xx 4200) = 5/42 ^circ "C"`
= 0.119 ° C = 0.12 ° C.
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[Use: Specific heat capacity of water = 4200 Jkg-1K-1, Latent heat of ice = 3.5 × 105 Jkg-1]
