Advertisements
Advertisements
प्रश्न
Two bodies having equal masses are moving with uniform speeds of v and 2v respectively. Find the ratio of their kinetic energies.
Advertisements
उत्तर
Let the masses of the two bodies be (m1) = m kg and (m2) = m kg .
Velocity of the first body, (v1) = v m/s
Velocity of the first body, (v2) = 2v m/s
The required ratio is-
= `"(Kinetic energy)"_1/"(Kinetic energy)"_2`
= `(1/2 (m_1)(v_1)^2)/(1/2 (m_2)(v_2)^2)`
So put the values to get ,
= `(1)^2/(2)^2`
= `1/4`
The ratio of K.E is, K.E of body 1 : K.E of body 2 = 1 : 4.
APPEARS IN
संबंधित प्रश्न
State the condition under which the mechanical energy is conserved.
A metal ball of mass 2 kg is allowed to fall freely from rest from a height of 5 m above the ground. Taking g = 10 m s−2, calculate:
- the potential energy possessed by the ball when it is initially at rest.
- the kinetic energy of the ball just before it hits the ground?
State whether the object possess kinetic energy, potential energy, or both :
A man climbing a hill _____________.
State whether the object possess kinetic energy, potential energy, or both :
A bird running on the ground ____________.
What kind of energy is possessed by the following?
A stretched rubber band _____________
What type of energy is possessed : by the piece of stone which is thrown away on releasing the stretched rubber strings of catapult?
A boy weighing 40 kg makes a high jump of 1.5 m.
What is his kinetic energy at the highest point?
Name the device or machine which convert :
Chemical energy into electrical energy.
Name the device or machine which convert :
Chemical energy into kinetic energy (or mechanical energy).
Fill in the blanks with suitable words :
The principle of ___________ of energy says energy can be transformed from one form to another, but it cannot be ___________ or ___________.
